feat(js): m08 stream (event streams as pure automata) with tests
Co-Authored-By: Claude Sonnet 5.5 <[email protected]>
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co-authored by
Claude Sonnet 5.5
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64135499b0
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584f1d4825
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// m08 stream: an event stream is a pure automaton (a Mealy machine).
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// Stream<A> = { step: input => [outputs, nextStream] }
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// There is no hidden state: whatever a stream "remembers" lives in the next stream it returns.
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// Sources may return themselves as the next stream, since they remember nothing.
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export const keyDowns = { step: (i) => [i.tag === 'KeyDown' ? [i.key] : [], keyDowns] }
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export const keyUps = { step: (i) => [i.tag === 'KeyUp' ? [i.key] : [], keyUps] }
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// `last` is the time of the previous Time input. Multiples of ms in (last, t] fire, ascending.
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const intervalFrom = (ms, last) => ({
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step: (i) => {
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if (i.tag !== 'Time') return [[], intervalFrom(ms, last)]
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const first = Math.floor(last / ms) + 1
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const count = Math.max(0, Math.floor(i.t / ms) - first + 1)
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return [Array.from({ length: count }, (_, n) => (first + n) * ms), intervalFrom(ms, i.t)]
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},
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})
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export const interval = (ms) => intervalFrom(ms, 0)
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// Each combinator steps its inputs and wraps the *next* streams in the same combinator.
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export const map = (s, f) => ({
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step: (i) => {
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const [out, next] = s.step(i)
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return [out.map(f), map(next, f)]
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},
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})
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export const filter = (s, p) => ({
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step: (i) => {
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const [out, next] = s.step(i)
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return [out.filter(p), filter(next, p)]
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},
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})
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export const filterMap = (s, f) => filter(map(s, f), (b) => b !== null)
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export const merge = (a, b) => ({
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step: (i) => {
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const [outA, nextA] = a.step(i)
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const [outB, nextB] = b.step(i)
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return [[...outA, ...outB], merge(nextA, nextB)]
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},
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})
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// The accumulator travels in the arguments of the next scan, not in a variable.
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export const scan = (s, f, z) => ({
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step: (i) => {
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const [out, next] = s.step(i)
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const accs = out.reduce((xs, o) => [...xs, f(xs.length === 0 ? z : xs[xs.length - 1], o)], [])
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return [accs, scan(next, f, accs.length === 0 ? z : accs[accs.length - 1])]
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},
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})
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// Only the first step is special; afterwards we are just `next`.
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export const startWith = (s, v) => ({
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step: (i) => {
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const [out, next] = s.step(i)
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return [[v, ...out], next]
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},
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})
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export const run = (s, inputs) =>
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inputs.reduce(
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([outs, stream], i) => {
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const [out, next] = stream.step(i)
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return [[...outs, ...out], next]
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},
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[[], s],
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)[0]
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@@ -0,0 +1,46 @@
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import { todo } from './todo.js'
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/**
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* An event stream as a pure automaton (a Mealy machine).
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* `Stream<A> = { step: input => [outputs, nextStream] }`: feed one input, get the (possibly empty) array
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* of outputs it produced and the stream to use for the next input. Nothing is mutated, so a stream value
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* can be run any number of times with the same results.
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* Inputs: `{tag:'Time', t}`, `{tag:'KeyDown', key}`, `{tag:'KeyUp', key}`.
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*/
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/** Emits the `key` of every KeyDown input; ignores everything else. */
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export const keyDowns = { step: () => todo('m08') }
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/** Emits the `key` of every KeyUp input; ignores everything else. */
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export const keyUps = { step: () => todo('m08') }
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/**
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* On `Time t`, emits every multiple `k*ms` with `last < k*ms <= t`, ascending, where `last` starts at 0
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* and becomes `t` afterwards. A big time jump can emit several values. Ignores key inputs.
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* Hint: write a private helper that carries `last`.
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*/
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export const interval = (ms) => todo('m08')
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/** Apply `f` to every output of `s`. */
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export const map = (s, f) => todo('m08')
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/** Keep only the outputs of `s` for which `p` is true. */
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export const filter = (s, p) => todo('m08')
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/** Apply `f` to every output of `s`; `f` returns a value or `null`, and nulls are dropped. */
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export const filterMap = (s, f) => todo('m08')
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/** Both streams step on every input; the outputs of `a` come before the outputs of `b`. */
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export const merge = (a, b) => todo('m08')
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/** Fold the outputs of `s` into an accumulator, starting from `z`; emits each new accumulator (not `z` itself). */
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export const scan = (s, f, z) => todo('m08')
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/**
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* Emit `v` once, before the outputs of the first step; later steps are unaffected.
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* Note: streams only act when an input arrives, so if no input ever arrives, `v` is never emitted.
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*/
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export const startWith = (s, v) => todo('m08')
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/** Feed all inputs through the stream and collect every output, in order. A pure fold (reduce). */
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export const run = (s, inputs) => todo('m08')
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@@ -0,0 +1,70 @@
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import test from 'node:test'
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import assert from 'node:assert/strict'
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import { keyDowns, keyUps, interval, map, filter, filterMap, merge, scan, startWith, run } from '../src/stream.js'
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import { freeze as deepFreeze } from './helpers.js'
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const time = (t) => ({ tag: 'Time', t })
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const down = (key) => ({ tag: 'KeyDown', key })
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const up = (key) => ({ tag: 'KeyUp', key })
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const inputs = (...xs) => deepFreeze(xs)
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test('m08 keyDowns emits keys of KeyDown inputs only', () =>
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assert.deepStrictEqual(run(keyDowns, inputs(down('a'), time(5), up('a'), down('b'))), ['a', 'b']))
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test('m08 keyUps emits keys of KeyUp inputs only', () =>
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assert.deepStrictEqual(run(keyUps, inputs(down('a'), time(5), up('a'), down('b'), up('b'))), ['a', 'b']))
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test('m08 run of no inputs is empty', () =>
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assert.deepStrictEqual(run(keyDowns, []), []))
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test('m08 interval emits each multiple once as time passes', () =>
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assert.deepStrictEqual(run(interval(10), inputs(time(5), time(10), time(35))), [10, 20, 30]))
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test('m08 interval emits several multiples after one big time jump', () =>
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assert.deepStrictEqual(run(interval(10), inputs(time(35))), [10, 20, 30]))
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test('m08 interval ignores key inputs', () =>
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assert.deepStrictEqual(run(interval(10), inputs(down('a'), up('a'))), []))
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test('m08 map transforms every output', () =>
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assert.deepStrictEqual(run(map(keyDowns, (k) => k + '!'), inputs(down('a'), down('b'))), ['a!', 'b!']))
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test('m08 filter keeps outputs satisfying the predicate', () =>
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assert.deepStrictEqual(run(filter(keyDowns, (k) => k !== 'a'), inputs(down('a'), down('b'))), ['b']))
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test('m08 filterMap transforms outputs and drops nulls', () =>
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assert.deepStrictEqual(
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run(filterMap(keyDowns, (k) => (k === 'a' ? null : k.toUpperCase())), inputs(down('a'), down('b'))),
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['B']))
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test('m08 merge puts outputs of the first stream before the second at the same input', () =>
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assert.deepStrictEqual(
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run(merge(map(keyDowns, (k) => 'first ' + k), map(keyDowns, (k) => 'second ' + k)), inputs(down('x'))),
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['first x', 'second x']))
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test('m08 merge interleaves sources by input order', () =>
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assert.deepStrictEqual(
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run(merge(interval(10), map(keyDowns, () => -1)), inputs(time(10), down('a'), time(20))),
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[10, -1, 20]))
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test('m08 scan emits each new accumulator, not the initial value', () =>
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assert.deepStrictEqual(run(scan(keyDowns, (n) => n + 1, 0), inputs(down('a'), up('a'), down('b'), down('c'))), [1, 2, 3]))
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test('m08 scan passes the output to the folding function', () =>
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assert.deepStrictEqual(run(scan(keyDowns, (acc, k) => acc + k, ''), inputs(down('a'), down('b'))), ['a', 'ab']))
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test('m08 startWith emits the value once, before the outputs of the first step', () =>
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assert.deepStrictEqual(run(startWith(keyDowns, 'init'), inputs(down('a'), down('b'))), ['init', 'a', 'b']))
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test('m08 startWith emits at the first input even if that step has no outputs', () =>
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assert.deepStrictEqual(run(startWith(keyDowns, 'init'), inputs(time(1), down('a'))), ['init', 'a']))
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test('m08 startWith emits nothing when no input ever arrives', () =>
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assert.deepStrictEqual(run(startWith(keyDowns, 'init'), []), []))
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test('m08 running the same stream value twice gives the same outputs', () => {
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const s = scan(merge(interval(10), map(keyDowns, () => 100)), (a, x) => a + x, 0)
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const xs = inputs(time(25), down('a'), time(40))
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assert.deepStrictEqual(run(s, xs), run(s, xs))
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assert.deepStrictEqual(run(s, xs), [10, 30, 130, 160, 200])
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})
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